What is the SI unit of electric flux?
Concept Overview:
Electric flux (\( \Phi_E \)) represents the total electric field passing through a given surface. It is defined as the surface integral of the electric field over that surface: \[ \Phi_E = \vec{E} \cdot \vec{A} \] According to Gauss’s law: \[ \Phi_E = \frac{Q}{\varepsilon_0} \] Using either expression, we can determine the SI unit of electric flux.
Step 1: Unit of Electric Field
The SI unit of electric field \( E \) is: \[ \text{N/C} \quad \text{or} \quad \text{V/m} \]
Step 2: Unit of Area
The SI unit of area \( A \) is: \[ \text{m}^2 \]
Step 3: Unit of Electric Flux
Multiplying the units: \[ (\text{V/m}) \times (\text{m}^2) = \text{V·m} \] Alternatively: \[ (\text{N/C}) \times (\text{m}^2) = \text{N·m}^2/\text{C} \] Both \( \text{V·m} \) and \( \text{N·m}^2/\text{C} \) are equivalent SI units of electric flux.
A point charge \(q = 1\,\mu\text{C}\) is located at a distance \(2\,\text{cm}\) from one end of a thin insulating wire of length \(10\,\text{cm}\) having a charge \(Q = 24\,\mu\text{C}\), distributed uniformly along its length, as shown in the figure. Force between \(q\) and wire is ________ N. 