Step 1: Approach
Use the Arrhenius equation to see what a catalyst must change.
Step 2: Equation
\[ k = A e^{-E_a/RT} \]
Rate rises when $k$ rises. At the same temperature, $k$ can rise a lot only if $E_a$ becomes smaller.
Step 3: Conclusion
So a catalyst lowers the activation energy. It leaves the overall energy change and the equilibrium constant alone, and it does not add energy. Option (D) is the correct one.
Final Answer:
A catalyst lowers the activation energy, option (D).
\[ \boxed{\text{Decreases the activation energy}} \]