What is the number of moles of H atoms required for complete reduction of one mole acetonitrile?
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Each $\pi$-bond in an organic molecule requires 2 atoms of hydrogen (or 1 mole of $H_2$ gas) for complete saturation. A nitrile ($-C \equiv N$) has two $\pi$-bonds, thus demanding 4 hydrogen atoms total.
Step 1: Understanding the Concept:
Reduction of a nitrile ($R-C \equiv N$) to a primary amine ($R-CH_2-NH_2$) involves adding hydrogen across the triple bond. Step 2: Formula Application:
$CH_3CN + 4[H] \rightarrow CH_3CH_2NH_2$. Step 3: Explanation:
Acetonitrile ($CH_3CN$) has a carbon-nitrogen triple bond. To reach the saturated amine (ethylamine), two hydrogen atoms must be added to the carbon and two to the nitrogen. This requires a total of 4 hydrogen atoms (or 2 moles of $H_2$ gas). Step 4: Final Answer:
The number of moles of H atoms required is 4.