Question

What is the importance of Sandmeyer's reaction?

• A. To obtain R-I from R-Cl
• B. To obtain Ar-X by replacing diazo group of \(\text{AR-N}_2^+\text{-X}^-\) using \(\text{CuCl}\) / \(\text{HCl}\)
• C. To obtain R-F from R-Cl using AgF
• D. To obtain \(\text{R-CH}_2\text{-R}\) from R-CO-R using Zn-Hg / HCl

Hint:

Sandmeyer reaction replaces the diazonium group by Cl or Br using CuCl or CuBr.

Answer 1

The Correct Option is B

Step 1: Idea:
Match each named reaction with its reagents.

Step 2: Matching:
Zn-Hg with HCl: Clemmensen. Alkyl chloride with NaI in dry acetone: Finkelstein. Alkyl chloride with AgF or $\text{Hg}_2\text{F}_2$: Swarts. Diazonium salt with Cu(I) halide: Sandmeyer. Only B describes the last one.

Final Answer:
Sandmeyer reaction gives Ar-X from the diazonium salt, option (B). \[ \boxed{\text{Ar-X from diazonium salt using CuCl/HCl}} \]