Question:medium

Identify the lanthanoid that exhibits zero effective magnetic moment in +3 state.

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$La^{3+}$ ($4f^0$) and $Lu^{3+}$ ($4f^{14}$) are the only lanthanoid ions with zero magnetic moment.
Updated On: May 16, 2026
  • Ho
  • Lu
  • Pr
  • Er
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Question:
A zero effective magnetic moment (\( \mu_{eff} = 0 \)) occurs when an ion has no unpaired electrons (all electrons are paired).
Step 2: Detailed Explanation:
The electronic configuration of lanthanoids in the +3 oxidation state involves losing 2 electrons from the \( 6s \) orbital and 1 from the \( 5d \) or \( 4f \) orbital.
- \( Ho^{3+} \): Has unpaired electrons in \( 4f \) subshell.
- \( Lu^{3+} \): Lutetium (\( Z = 71 \)) has ground state config \( [Xe] 4f^{14} 5d^{1} 6s^{2} \). In \( Lu^{3+} \), it loses \( 5d^1 \) and \( 6s^2 \), leaving \( [Xe] 4f^{14} \). The \( 4f \) subshell is completely filled, meaning \( n = 0 \).
- \( Pr^{3+} \): Has unpaired electrons.
- \( Er^{3+} \): Has unpaired electrons.
Since \( Lu^{3+} \) has zero unpaired electrons, its magnetic moment is zero.
Step 3: Final Answer:
Lutetium (Lu) exhibits zero effective magnetic moment in the +3 state.
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