Question

What is the hybridization of the central sulfur atom in \(SF_6\)?

• A. \(sp^3\)
• B. \(sp^3d\)
• C. \(sp^3d^2\)
• D. \(sp^2\)

Hint:

Hybridization vs steric number: 2 → \(sp\) 3 → \(sp^2\) 4 → \(sp^3\) 5 → \(sp^3d\) 6 → \(sp^3d^2\)

Answer 1

The Correct Option is C

Step 1: Understanding the Question:
We need to identify the orbital mixing state (hybridization) of the Sulfur atom in the Sulfur hexafluoride molecule.
Step 2: Key Formula or Approach:
Steric Number (SN) = (Number of bonded atoms) + (Number of lone pairs on central atom).
Step 3: Detailed Explanation:
1. Valence Electrons: Sulfur has 6 valence electrons.
2. Bonding: It forms 6 single bonds with 6 Fluorine atoms.
3. Lone Pairs: All 6 electrons are used in bonding, so there are 0 lone pairs.
4. Steric Number: \(6 + 0 = 6\).
A steric number of 6 corresponds to \(sp^3d^2\) hybridization.
This results in an Octahedral molecular geometry.
Step 4: Final Answer:
The hybridization of sulfur in \(SF_6\) is \(sp^3d^2\).