Set up the sensible heat equation directly in consistent units.
\[Q = m \times c \times \Delta T\]
Here \(m = 2 \text{ tons} = 2000 \text{ kg}\), \(c = 0.1 \text{ kcal/kg}^\circ C\), and \(\Delta T = 25 - 5 = 20^\circ C\).
\[Q = 2000 \times 0.1 \times 20\]
\[Q = 200 \times 20 = 4000 \text{ kcal}\]
\[\boxed{Q = 4000 \text{ kcal}}\]