7.0 kW
10.2 kW
8.1 kW
12.3 kW
To solve this problem, we need to calculate the power generated by the turbine using the potential energy of the falling water, accounting for energy losses due to friction.
First, we calculate the potential energy of the water falling from a height:
The potential energy (PE) of a mass \(m\) at height \(h\) is given by the formula:
\(PE = m \cdot g \cdot h\)
where:
Substituting the given values, we find:
\(PE = 15 \times 10 \times 60 = 9000 \text{ J/s} = 9000 \text{ W}\)
Since 10% of the input energy is lost due to friction, only 90% of the potential energy is converted to useful power.
The useful power (Puseful) is calculated as:
\(P_{\text{useful}} = 0.9 \times 9000 = 8100 \text{ W}\)
Finally, convert watts to kilowatts:
\(P_{\text{useful}} = \frac{8100}{1000} = 8.1 \text{ kW}\)
Thus, the power generated by the turbine is 8.1 kW. The correct answer is:
8.1 kW