Volume of 3%solution of sodium carbonate necessary to neutralise a litre of 0.1 N sulphuric acid is
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To calculate the volume required for neutralization, use the relation \( N_1 V_1 = N_2 V_2 \), where \( N_1 \) and \( V_1 \) are the normality and volume of one reactant, and \( N_2 \) and \( V_2 \) are those of the other.