To compare:
(1.1)10000 and 1000
Step 1: Rewrite using Binomial Theorem
1.1 = 1 + 0.1
∴ (1.1)10000 = (1 + 0.1)10000
Step 2: Expand first few terms
(1 + x)n = 1 + nx + nC2x2 + …
Using x = 0.1 and n = 10000:
(1.1)10000 = 1 + 10000(0.1) + 10000C2(0.1)2 + …
= 1 + 1000 + 10000C2(0.01) + …
Step 3: Estimate the second term
10000C2 = (10000 × 9999) / 2 ≈ 5 × 107
So,
10000C2(0.01) ≈ 5 × 107 × 0.01 = 5 × 105 = 500000
Step 4: Compare values
(1.1)10000 > 1 + 1000 + 500000
(1.1)10000 > 501001
Clearly,
501001 > 1000
Conclusion:
(1.1)10000 is much larger than 1000.