Given:
(√3 + √2)6 − (√3 − √2)6
Step 1: Let
x = √3 + √2, y = √3 − √2
Required value = x6 − y6
Step 2: Find x + y and xy
x + y = 2√3
xy = (√3 + √2)(√3 − √2) = 3 − 2 = 1
Step 3: Use identity
x6 − y6 = (x − y)(x + y)(x2 + y2)(x2 − xy + y2)
Step 4: Compute required terms
x − y = 2√2
x2 + y2 = (x + y)2 − 2xy = (2√3)2 − 2 = 12 − 2 = 10
x2 − xy + y2 = (x2 + y2) − xy = 10 − 1 = 9
Step 5: Substitute values
x6 − y6 = (2√2)(2√3)(10)(9)
= 4√6 × 90
= 360√6
Final Answer:
(√3 + √2)6 − (√3 − √2)6 = 360√6