Question:medium

Using a Punnett square, work out the distribution of an autosomal phenotypic feature in the first filial generation after a cross between a homozygous female and a heterozygous male for a single locus.

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In a cross between a homozygous dominant female and a heterozygous male, 50% of the offspring will be heterozygous and 50% will be homozygous dominant, all exhibiting the dominant trait.
Updated On: Jan 13, 2026
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Solution and Explanation

Punnett Square: Autosomal Phenotypic Distribution

This Punnett square demonstrates a cross between a homozygous dominant female (AA) and a heterozygous male (Aa) for a single gene.

Punnett Square:

A (from female parent)A (from female parent)
A (from male parent)AAAA
a (from male parent)AaAa

Genotypic Distribution:

  • 50% AA (homozygous dominant genotype)
  • 50% Aa (heterozygous genotype)

Phenotypic Distribution:

Given that both the AA and Aa genotypes result in the dominant phenotype, 100% of the offspring will display the dominant characteristic.

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