Question:easy

Unit of rate constant of a first order reaction is —

Show Hint

Use unit = (mol L-1)^(1-n) s^-1 with n = 1; the concentration term cancels out.
Updated On: Jul 10, 2026
  • \( mol\ L^{-1}\ s^{-1} \)
  • \( s^{-1} \)
  • \( mol^{-1}\ L\ s^{-1} \)
  • None of these
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Use the general formula for the unit of a rate constant, \( (concentration)^{1-n}(time)^{-1} \), where \(n\) is the order.
Step 2: Put \(n = 1\) for a first order reaction: \( (mol\ L^{-1})^{1-1}(s)^{-1} = (mol\ L^{-1})^{0}\,s^{-1} \).
Step 3: Anything raised to power zero equals 1, so the concentration term disappears completely and only the time term survives.
Step 4: Hence the unit is simply \( s^{-1} \) (or \( min^{-1} \)), which is why the half-life of a first order reaction is independent of the starting concentration.
\[\boxed{k_{first\ order}=s^{-1}}\]
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