Question:medium

Two subatomic particles 1 and 2, with the same kinetic energies, have their de-Broglie wavelengths as \( \lambda_1 \) and \( \lambda_2 \) and masses as 3 m and 6 m respectively. Determine the ratio \( \lambda_1 : \lambda_2 \).

Show Hint

For particles with the same kinetic energy, the de-Broglie wavelength is inversely proportional to the square root of the particle’s mass. The heavier particle will have a shorter wavelength.
Updated On: May 5, 2026
  • 2 : 1
  • 1 : 2
  • \( \sqrt{2} : 1 \)
  • 1 : \( \sqrt{2} \)
Show Solution

The Correct Option is C

Solution and Explanation

Was this answer helpful?
0