Question:medium
Two samples A and B of gas initially at the same pressure and temperature. They are compressed from volume \(V\) to \(\frac{V}{2}\) (A isothermally and B adiabatically). The relation between pressure of the gas A (\(P_A\)) and pressure of gas B (\(P_B\)) is
Two samples A and B of gas initially at the same pressure and temperature. They are compressed from volume \(V\) to \(\frac{V}{2}\) (A isothermally and B adiabatically). The relation between pressure of the gas A (\(P_A\)) and pressure of gas B (\(P_B\)) is
Show Hint
Adiabatic compression heats the gas, so its pressure rises more.
Updated On: Oct 1, 2026
- \(P_A < P_B\)
- \(P_A > P_B\)
- \(P_A = P_B\)
- \(P_A = 2P_B\)
Show Solution
The Correct Option is A
Solution and Explanation
Step 1: Physical reasoning
In compression B no heat leaves, so the temperature rises, and pressure rises beyond the value at constant temperature. Hence $P_A<P_B$.
Final Answer:
Option (A). \[ \boxed{\text{(A)}} \]
In compression B no heat leaves, so the temperature rises, and pressure rises beyond the value at constant temperature. Hence $P_A<P_B$.
Final Answer:
Option (A). \[ \boxed{\text{(A)}} \]
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