Compute the equivalent resistance of the parallel resistors: \[ \frac{1}{R_{\text{parallel}}} = \frac{1}{4} + \frac{1}{6} = \frac{5}{12} \] \[ R_{\text{parallel}} = \frac{12}{5} = 2.4 \, \Omega \] The total circuit resistance is: \[ R_{\text{total}} = R_{\text{parallel}} + 2 \, \Omega = 2.4 + 2 = 4.4 \, \Omega \] Apply Ohm's law to find the total current: \[ I = \frac{V}{R_{\text{total}}} = \frac{12}{4.4} \approx 2.73 \, A \] Calculate the total power dissipated: \[ P = I^2 R_{\text{total}} = (2.73)^2 \times 4.4 \approx 32.7 \, W \] The total power dissipated is \( 32.7 \, W \).