Question:medium

In a circuit, a current of \( 2 \, \text{A} \) flows through a resistor of resistance \( 5 \, \Omega \). Calculate the power dissipated in the resistor.

Show Hint

Power dissipation in a resistor is proportional to the square of the current. Ensure to use the correct formula depending on what quantities are given in the problem.
Updated On: Jan 13, 2026
  • \( 20 \, \text{W} \) 
     

  • \( 5 \, \text{W} \)
  • \( 15 \, \text{W} \)
  • \( 10 \, \text{W} \) 
     

Show Solution

The Correct Option is A

Solution and Explanation

Provided Information:

  • Current: \( I = 2 \, \text{A} \)
  • Resistance: \( R = 5 \, \Omega \)

Procedure:

Apply the formula for power dissipation in a resistor:

\[ P = I^2 R \] Where: - \( P \) denotes power dissipated, - \( I \) represents current, - \( R \) signifies resistance.

Calculation:

Substitute the provided values into the formula:

\[ P = (2 \, \text{A})^2 \times 5 \, \Omega \] \[ P = 4 \times 5 = 20 \, \text{W} \]

✅ Result:

The calculated power dissipation is \( \boxed{20 \, \text{W}} \).

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