Two positive charges of +Q each are placed at the corners A and B of an equilateral triangle ABC of side R. The net electric potential at C, in terms of K is (\(K = \frac{Q}{4\pi\epsilon_0 R}\))
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Potentials add up directly as numbers (scalars), whereas electric fields add up as vectors. Never use vector addition (like \(\sqrt{E_A^2+E_B^2...}\)) for potential problems.