Question:medium

Two positive charges of +Q each are placed at the corners A and B of an equilateral triangle ABC of side R. The net electric potential at C, in terms of K is (\(K = \frac{Q}{4\pi\epsilon_0 R}\))

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Potentials add up directly as numbers (scalars), whereas electric fields add up as vectors. Never use vector addition (like \(\sqrt{E_A^2+E_B^2...}\)) for potential problems.
Updated On: Jun 24, 2026
  • \(\sqrt{2}K\)
  • \(\sqrt{3}K\)
  • 2K
  • K
  • \(\sqrt{5}K\)
Show Solution

The Correct Option is C

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