Question:medium

Two parallel conductors a and b separated by distance \(d\) carry the same current. If the distance is doubled, the ratio of forces on conductor b before and after separation is:

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Force between parallel current-carrying wires varies inversely with separation distance.
Updated On: Jun 19, 2026
  • 2:1
  • 6:2
  • 1:4
  • 4:6
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The Correct Option is A

Solution and Explanation

Step 1: Force per unit length between parallel currents.
F ∝ 1/d.

Step 2: Initial force.

F₁ ∝ 1/d.

Step 3: Force after doubling separation.

F₂ ∝ 1/(2d).

Step 4: Forming the ratio.

F₁ : F₂ = (1/d) : (1/2d).

Step 5: Simplifying.

F₁ : F₂ = 2 : 1.

Step 6: Conclusion.

The ratio is 2:1.
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