Question:hard

Two long parallel wires carrying currents \(8\)A and \(15\)A in opposite directions are placed at a distance of \(7\) cm from each other. A point P is at equidistant from both the wires such that the lines joining the point P to the wires are perpendicular to each other. The magnetic field at P is ___ \(\times 10^{-6}\) T. (Given: \(\sqrt{2} = 1.4\), \(μ_0 = 4π\times 10^{-7}\) SI unit)

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The point is $5$ cm from each wire, and the two fields are perpendicular.
Updated On: Oct 1, 2026
  • \(62\)
  • \(65\)
  • \(68\)
  • \(70\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Use components
Place P at the origin with wire 1 along one axis and wire 2 along the other. $\vec B_1$ points along the second axis and $\vec B_2$ along the first axis, with magnitudes $32\times10^{-6}$ and $60\times10^{-6}$ T.
The resultant magnitude is $\sqrt{32^2+60^2}=\sqrt{4624}=68$ in units of $10^{-6}$ T.

Final Answer:
Option (C). \[ \boxed{\text{(C)}} \]
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