Question

Two light waves amplitudes in the ratio \(3:1\) produce interference. The ratio of the maximum to minimum intensity is

• A. \(9:4\)
• B. \(16:9\)
• C. \(3:2\)
• D. \(4:1\)

Hint:

Intensity ratio is $\frac{(a_1+a_2)^2}{(a_1-a_2)^2}$.

Answer 1

The Correct Option is D

Step 1: From intensities
$I_1:I_2=9:1$. $I_{max}=(3+1)^2=16$ and $I_{min}=(3-1)^2=4$ in the same units. Ratio $4:1$.

Final Answer:
Option (D). \[ \boxed{\text{(D)}} \]