List of top Physics Questions on wave interference asked in MHT CET

In YDSE, the intensity where path difference is (\frac{\lambda}{4}) is (\frac{K}{4}). The intensity at a point when path difference is ' (\lambda) ' will be

Two waves of same frequency ( $n$ ) are approaching each other with same velocity $12\text{ m/s}$ along the same linear path and interfere. The distance between two consecutive nodes is

In YDSE, the intensity where path difference is (\frac{\lambda}{4}) is (\frac{K}{4}). The intensity at a point when path difference is ' (\lambda) ' will be

In YDSE, the intensity where path difference is (\frac{\lambda}{4}) is (\frac{K}{4}). The intensity at a point when path difference is ' (\lambda) ' will be

Assertion (A): When two waves of equal amplitude and a phase difference of \( \frac{\pi}{2} \) interfere, the resulting intensity is equal to the intensity of one wave. Reason (R): In interference, the resultant intensity is always the sum of individual intensities if the phase difference is non-zero.

In Young's double slit experiment, fringe width is \( 1.4 \text{ mm} \) with light of wavelength \( 6000\,\text{\AA} \). If the light of wavelength \( 5400\,\text{\AA} \) is used, with no other change in the experimental set up. The change in fringe width is

When two light waves each of amplitude '$A$' and having a phase difference of $\frac{\pi}{2}$ superimposed then the amplitude of resultant wave is

On replacing a thin film of mica of thickness $12 \times 10^{-5}$ cm in the path of one of the interfering beams in Young's double slit experiment using monochromatic light, the fringe pattern shifts through a distance equal to the width of bright fringe. If $\lambda = 6 \times 10^{-5}$ cm, the refractive index of mica is