The force between two parallel conductors carrying currents is determined using equations derived from Ampère's Law and the Biot-Savart Law. For two parallel currents, I1 and I2, separated by a distance d in a vacuum, the force per unit length f is:
\( f = \frac{\mu_0}{2\pi} \cdot \frac{I_1I_2}{d} \)
Here, μ0 represents the permeability of free space. The total force F on a conductor of length L is calculated as:
\( F = f \cdot L = \left(\frac{\mu_0}{2\pi} \cdot \frac{I_1I_2}{d}\right) \cdot L \)
This equation shows that the force F is directly proportional to the product I1 × I2 × L.
Consequently, the force on a length L of one conductor is proportional to \(I_1 \times I_2 \times L\).
Three long straight wires carrying current are arranged mutually parallel as shown in the figure. The force experienced by \(15\) cm length of wire \(Q\) is ________. (\( \mu_0 = 4\pi \times 10^{-7}\,\text{T m A}^{-1} \)) 