Question

Two forces \(F_1\) and \(F_2\) are applied on two rods \(P\) and \(Q\) of same materials such that elongation in rods are same. If ratio of their radii is \(x : y\) and ratio of length is \(m : n\), then ratio of \(F_1 : F_2\) is

• A. \(\bigg(\frac{y}{x}\bigg)^2\frac{ n}{m}\)
• B. \(\bigg(\frac{x}{y}\bigg)^2 \frac{n}{m}\)
• C. \(\bigg(\frac{y}{x}\bigg)^2 \frac{m}{n}\)
• D. \(\bigg(\frac{y}{x}\bigg)^2 \frac{m}{n}\)

Answer 1

The Correct Option is B

The correct option is (B): \(\bigg(\frac{x}{y}\bigg)^2 \frac{n}{m}\)