Question:medium

A balloon and its content having mass \( M \) is moving up with an acceleration \( a \). The mass that must be released from the content so that the balloon starts moving up with an acceleration \( 3a \) will be:

Show Hint

In problems involving forces and accelerations, remember to apply Newton’s second law for both the initial and final conditions, and use the relationship between mass and acceleration carefully.
Updated On: Jan 14, 2026
  • \( \frac{2Ma}{3a + g} \)
  • \( \frac{3Ma}{2a - g} \)
  • \( \frac{3Ma}{2a + g} \)
  • \( \frac{2Ma}{3a - g} \)
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Initial Force Equation

The force \( F \) acting on the balloon with initial mass \( m \) is described by: \[ F - mg = ma \]

Step 2: Force Upon Releasing Mass \( x \)

When mass \( x \) is released, the force equation is: \[ F = ma + mg \]

Step 3: Force After Releasing Mass \( x \)

Following the release of mass \( x \), the equation is: \[ F - (m - x)g = (m - x) 3a \]

Step 4: Substitute \( F \) Value

Substitute \( F \) from the previous step into this equation: \[ Ma + mg - mg + xg = 3ma - 3xa \]

Step 5: Solve for \( x \)

The solution for \( x \) is: \[ x = \frac{2ma}{g + 3a} \]

Final Answer: \[ x = \frac{2ma}{g + 3a} \]

Was this answer helpful?
0


Questions Asked in JEE Main exam