Question:medium

Two equal forces each of magnitude P acting at a point with an angle of \( (\alpha) \), then the resultant force is

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The resultant of two equal vectors always bisects the angle between them. Geometrically, this splits the vector addition parallelogram into two congruent isosceles triangles. Projecting the vectors along this central bisection line gives \( P\cos(\alpha/2) + P\cos(\alpha/2) = 2P\cos(\alpha/2) \) directly!

Updated On: Jul 9, 2026

\( 2\text{ P}\sin\left(\frac{\alpha}{2}\right) \)
\( 2\text{ P}\cot\left(\frac{\alpha}{2}\right) \)
\( 2\text{ P}\cos\left(\frac{\alpha}{2}\right) \)
\( 2\text{ P}\tan\left(\frac{\alpha}{2}\right) \)

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The Correct Option is C

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