A ball of mass 0.1 kg, initially at rest, is dropped from height of 1 m. Ball hits the ground and bounces off the ground. Upon impact with the ground, the velocity reduces by 20%. The height (in m) to which the ball will rise is:
Show Hint
For any bouncing problem where velocity is scaled by a factor \(e\) (the coefficient of restitution), the height scales as the square of that factor:
\[
h_{\text{new}} = e^2 \times h_{\text{initial}}
\]
Here, \(e = 0.8\), so \(h_{\text{new}} = (0.8)^2 \times 1 = 0.64 \text{ m}\). Notice that the mass of the ball (0.1 kg) does not affect the kinematic motion.