We are asked to find probabilities when two different coins are tossed simultaneously.
Step 1: Sample Space
- Let the two coins be Coin 1 and Coin 2.
- Each coin can land as Head (H) or Tail (T).
- The sample space for two coins is:
\[
S = \{ (H, H), (H, T), (T, H), (T, T) \}
\]
- Total number of outcomes, \(n(S) = 4\).
(i) Probability of at least one head
- "At least one head" means 1 or 2 heads appear.
- Favorable outcomes: \((H, H), (H, T), (T, H)\)
- Number of favorable outcomes = 3
\[
P(\text{at least one head}) = \frac{3}{4}
\]
(ii) Probability of at most one tail
- "At most one tail" means 0 or 1 tail appears.
- Outcomes with 0 tail: \((H, H)\)
- Outcomes with 1 tail: \((H, T), (T, H)\)
- Total favorable outcomes = 3
\[
P(\text{at most one tail}) = \frac{3}{4}
\]
(iii) Probability of a head and a tail
- "A head and a tail" means one coin shows H and the other shows T.
- Favorable outcomes: \((H, T), (T, H)\)
- Number of favorable outcomes = 2
\[
P(\text{head and tail}) = \frac{2}{4} = \frac{1}{2}
\]
Answer:
(i) \(P = \frac{3}{4}\)
(ii) \(P = \frac{3}{4}\)
(iii) \(P = \frac{1}{2}\)