Question

Two dice are rolled together. The probability that sum of the numbers obtained is atmost 12, is

• A. 1
• B. 0
• C. \(\frac{1}{2}\)
• D. \(\frac{35}{36}\)

Hint:

An event that is certain to occur is called a sure event, and its probability is always 1.
Since the maximum sum on two dice can never exceed 12, any roll of the dice will satisfy the condition \(S \le 12\).
Recognizing this allows you to choose Option (A) instantly!

Answer 1

The Correct Option is A

Step 1: Find the largest possible sum of two dice.
Each face shows at most $6$, so the biggest possible total is $6+6=12$.
Step 2: Compare this to the condition asked.
"Atmost 12" means the sum $\le 12$. Since no roll can ever exceed $12$, this condition holds for every single outcome.
Step 3: State the probability of a certain event.
An event that always happens is a sure event with probability exactly $1$, matching option (A).
\[ \boxed{1} \]