Question:medium
Two copper wires of length $L$ and $2L$ have radii $r$ and $2r$ respectively. If they are subjected to the same tension force, the ratio of their extension ($\Delta L_1 / \Delta L_2$) is:
Two copper wires of length $L$ and $2L$ have radii $r$ and $2r$ respectively. If they are subjected to the same tension force, the ratio of their extension ($\Delta L_1 / \Delta L_2$) is:
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Use proportionality directly: $\Delta L \propto \frac{L}{r^2}$. Doubling the length doubles the extension, but doubling the radius quarter-sizes it. Net change is $2 \times \frac{1}{4} = \frac{1}{2}$, meaning the second wire stretches half as much.
Updated On: May 31, 2026
- $2 : 1$
- $1 : 2$
- $1 : 1$
- $4 : 1$
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The Correct Option is A
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