Question:medium

Two charged metallic spheres with radii \(R_1\) and \(R_2\) are brought in contact and then separated. The ratio of final charges \(Q_1\) and \(Q_2\) on the two spheres respectively will be _____.
Fill in the blank with the correct answer from the options given below

Updated On: Mar 27, 2026
  • \(\frac{Q_2}{Q_1}=\frac{R_1}{R_2}\)
  • \(\frac{Q_2}{Q_1}<\frac{R_1}{R_2}\)
  • \(\frac{Q_2}{Q_1}>\frac{R_1}{R_2}\)
  • \(\frac{Q_2}{Q_1}=\frac{R_2}{R_1}\)
Show Solution

The Correct Option is D

Solution and Explanation

Upon contact and subsequent separation of two charged metallic spheres with radii \(R_1\) and \(R_2\), charge redistribution occurs, resulting in equal potentials on both spheres. The potential \(V\) for a sphere with charge \(Q\) and radius \(R\) is defined as:
\(V=\frac{Q}{R}\)
Let \(Q_1\) and \(Q_2\) denote the charges on spheres with radii \(R_1\) and \(R_2\), respectively, after contact. Equating their potentials yields:
\(\frac{Q_1}{R_1}=\frac{Q_2}{R_2}\)
Rearranging this equation provides the ratio of the charges:
\(\frac{Q_2}{Q_1}=\frac{R_2}{R_1}\)
The derived relationship is:
\(\frac{Q_2}{Q_1}=\frac{R_2}{R_1}\)
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