Two bars A and B made of different material have same length. The coefficient of expansion and Young's modulus of bar B is twice that of bar A. If the temperature of both bars is increased by the same amount while preventing any expansion, then the ratio of stress developed in bar A to that in bar B is
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Thermal stress depends directly on the product of $\alpha$ and $E$ ($\sigma \propto \alpha E$). Since Bar B has twice the value for both properties, it experiences $2 \times 2 = 4$ times more internal thermal stress than Bar A.