Question:medium

Two air-filled capacitors of capacitances \(C_1\) and \(C_2\) are connected in parallel with a dc battery. After the capacitors are fully charged, a slab of dielectric constant \(K\) is inserted between the plates of each capacitor. How will the
• [(i)] charge on each capacitor, and
• [(ii)] energy stored in the capacitors be affected after the slab is introduced?

Show Hint

For a capacitor connected to a battery: \[ V=\text{constant} \] When a dielectric is inserted, \[ C' = KC \] Therefore, \[ Q'=KQ \] and \[ U'=KU \] Remember that charge and energy increase because the battery supplies additional charge to maintain the same voltage.
Show Solution

Solution and Explanation

Was this answer helpful?
0

Top Questions on capacitor with a dielectric