Question

Let a rod \(AB\) of length \(l\) having resistance \(r\) is moving perpendicular to a magnetic field \(B\) with constant velocity \(v\). If the ends of the rod are connected to a wire \(PQRS\) of negligible resistance, then current passing through the wire will be:

• A. \(\displaystyle \frac{Blv}{2r}\)
• B. \(\displaystyle \frac{Blv}{r}\)
• C. \(\displaystyle \frac{Blv}{4}\)
• D. \(\displaystyle \frac{3Blv}{4r}\)

Hint:

For a rod moving perpendicular to a magnetic field, induced emf is \(\varepsilon=Blv\). Then use \(I=\frac{\varepsilon}{R}\).

Answer 1

The Correct Option is B