Twenty seven drops of same size are charged at $220\text{ V}$ each. They combine to form a bigger drop. Calculate the potential of the bigger drop.}
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For $n$ identical droplets combining, the potential of the big drop is always $V_{big} = n^{2/3} \times V_{small}$. Here, $27^{2/3} = (3^3)^{2/3} = 3^2 = 9$.