Question:medium

To have zero active pressure intensity at the top of a wall in a cohesive soil, one should apply a uniform surcharge intensity of: (Where $C =$ cohesion and $\alpha =$ angle of failure plane with major principal plane)

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For cohesive soils, a surcharge is often needed to neutralize negative active pressure at the top of retaining walls.
Updated On: Feb 18, 2026
  • $2C \tan \alpha$
  • $2C \cot \alpha$
  • $-2C \tan \alpha$
  • $-2C \cot \alpha$
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The Correct Option is A

Solution and Explanation

Step 1: Active earth pressure in cohesive soil.
The general expression for active earth pressure at depth $z$ is: \[p_a = \gamma z K_a - 2C \sqrt{K_a}, \] where $K_a = \tan^2\left(45^\circ - \frac{\phi}{2}\right)$ and $C$ represents cohesion.

Step 2: Pressure at the top of the wall ($z=0$).
At $z=0$, the active earth pressure is: \[p_a = -2C \sqrt{K_a}. \] This negative value indicates tension at the top, which is not physically realistic.

Step 3: Application of surcharge $q$.
The expression for active earth pressure, modified to include a surcharge $q$, becomes: \[p_a = q K_a - 2C \sqrt{K_a}. \]

Step 4: Condition for zero pressure at the top.
For the pressure at the top to be zero ($p_a = 0$), the following condition must be met: \[q K_a = 2C \sqrt{K_a}. \] Solving for $q$: \[q = \frac{2C}{\sqrt{K_a}} = 2C \tan \alpha. \]

Step 5: Conclusion.
Therefore, the required uniform surcharge intensity to achieve zero pressure at the top of the wall is $2C \tan \alpha$.

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