Question

To get 300 MW electric power for half an hour, how much mass is to be completely converted into energy?

• A. \( 6 \times 10^{-2} \, \text{kg} \)
• B. \( 3 \times 10^{-6} \, \text{kg} \)
• C. \( 6 \times 10^{-3} \, \text{kg} \)
• D. \( 6 \times 10^{-6} \, \text{kg} \)

Hint:

Always convert power into total energy using \( E = Pt \) before applying \( E = mc^2 \).

Answer 1

The Correct Option is D