Question:medium

Three thin wires of equal length in suspension have the respective ratio of their area of cross section \(1:2:4\) and Young's moduli \(4:2:1\), then the ratio of their time periods due to attached at the other ends due to elongation is

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For wire oscillation, compare the product \(AY\). If \(AY\) is the same, the time period is the same.
Updated On: Apr 29, 2026
  • \(1:1:1\)
  • \(1:2:4\)
  • \(4:2:1\)
  • \(2:\sqrt{2}:1\)
  • \(1:\sqrt{2}:2\)
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The Correct Option is A

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