Question

Three persons A, B and C planned to have a running race among themselves. If the probability that A wins the race is three times that of B and the probability that B wins the race is \(\dfrac32\) times that of C, then the difference in probabilities of A and C to win the race is

• A. \(\dfrac23\)
• B. \(\dfrac12\)
• C. \(\dfrac5{14}\)
• D. \(\dfrac37\)

Hint:

When probabilities are given in ratios, first express them using a common variable, then use \[ \boxed{P(A)+P(B)+P(C)=1} \] to determine the unknown probability.

Answer 1

The Correct Option is B