Question:medium

Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all three apply for the same house is:

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Alternatively: the first person can choose any house (prob = 1). The second and third persons must choose that same house, each with probability $1/3$. Total probability $= 1 \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}$.

Updated On: Oct 6, 2026

$\frac{2}{9}$
$\frac{1}{9}$
$\frac{4}{9}$
$\frac{1}{27}$

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The Correct Option is B

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Three houses are available in a locality. Three persons apply for the houses. Each applies for one house without consulting others. The probability that all three apply for the same house is:

Show Hint

The Correct Option is B

Solution and Explanation

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