Question:medium

Three charges \( +q \) are placed at the corners of an equilateral triangle of side \( a \). What would be the total electrostatic potential energy (in terms of \( k \))?

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For symmetric charge distributions, calculate the potential energy for one pair and multiply by the number of pairs. In an equilateral triangle, there are 3 charge pairs.
Updated On: Nov 26, 2025
  • \( kq^2 / a \)
  • \( 2kq^2 / a \)
  • \( 3kq^2 / a \)
  • \( 4kq^2 / a \)
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The Correct Option is C

Solution and Explanation

The electrostatic potential energy of a system of point charges is defined as: \( U = \sum_{i > j} \frac{k q_i q_j}{r_{ij}} \). Here, \( k \) represents the Coulomb constant, \( q_i \) and \( q_j \) denote the charges, and \( r_{ij} \) is the distance separating the charges.

Step 1: Identify charge pairs.

The system comprises three charges, each with magnitude \( +q \), positioned at the vertices of an equilateral triangle with side length \( a \). The potential energy arises from the mutual interactions between these charges. The identified charge pairs are:

The interaction between charges at vertices 1 and 2.

The interaction between charges at vertices 2 and 3.

The interaction between charges at vertices 3 and 1.

Step 2: Calculate the potential energy for a single pair.

The potential energy for any given pair of charges is calculated as: \( U_{\text{pair}} = \frac{k q^2}{a}. \)

Step 3: Sum the potential energy across all pairs.

Given that an equilateral triangle has three pairs of charges:

\( U_{\text{total}} = 3 \cdot U_{\text{pair}} = 3 \cdot \frac{k q^2}{a}. \)

Therefore, the total potential energy is: \( U_{\text{total}} = \frac{3kq^2}{a}. \)

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