Question:medium

Three cards are drawn successively, without replacement from a pack of 52 well shuffled cards. The probability that first two cards are kings and the third card drawn is an ace is _____

Show Hint

For without replacement, denominator keeps decreasing.
Updated On: Apr 2, 2026
  • \( \frac{1}{135200} \)
  • \( \frac{2}{5525} \)
  • \( \frac{3}{5525} \)
  • \( \frac{3}{135200} \)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
Since cards are drawn without replacement, the total number of cards and the number of specific cards decrease with each draw. This is a case of dependent events.
Step 2: Formula Application:
1. Probability of 1st King ($K_1$) = $4/52$
2. Probability of 2nd King ($K_2$) = $3/51$ (one King and one card removed)
3. Probability of 3rd Ace ($A_3$) = $4/50$ (two cards removed, but all 4 Aces remain)
Step 3: Explanation:
Total Probability = $\frac{4}{52} \times \frac{3}{51} \times \frac{4}{50}$ $$P = \frac{1}{13} \times \frac{1}{17} \times \frac{2}{25} = \frac{2}{13 \times 17 \times 25} = \frac{2}{5525}$$
Step 4: Final Answer:
The probability is $2/5525$.
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