Question:medium

Three candidates "A", "B", "C" participated in an election. "A" gets 40% of the votes more than "B". "C" gets 20% votes more than "B". "A" also overtakes "C" by 4000 votes. If 90% voters voted and no invalid or illegal votes were cast, then what will be the number of voters in the voting list?

Show Hint

Write A and C as multiples of B, then use the given difference to solve for B.
Updated On: Jul 16, 2026
  • 72000
  • 80000
  • 70000
  • 78500
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Write the votes as a ratio.
$A : B : C = 1.4 : 1 : 1.2$. Multiply through by 5 to clear decimals: $A : B : C = 7 : 5 : 6$.

Step 2: Use the given gap between A and C in ratio terms.
In this ratio, $A - C$ corresponds to $7 - 6 = 1$ part. We are told this gap is 4000 votes, so 1 part $= 4000$.

Step 3: Find each candidate's votes and the total polled.
$A = 7 \times 4000 = 28000$, $B = 5 \times 4000 = 20000$, $C = 6 \times 4000 = 24000$. Total votes polled $= (7+5+6) \times 4000 = 18 \times 4000 = 72000$.

Step 4: Scale up to the full voter list.
This 72000 is 90% of the voting list, so the list size is $72000 \times \frac{10}{9} = 80000$.

Final Answer:
The ratio method confirms the voting list has 80000 voters. \[ \boxed{80000} \]
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