Question:medium

The work function of a photosensitive metallic surface is \( h\nu_0 \). If photons of energy \( (2.5)h\nu_0 \) fall on this surface, the electrons come out with maximum velocity ' v '. When the photon energy is increased to \( 7h\nu_0 \), the maximum velocity of photoelectrons will be

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- KE $\propto$ $(\nu - \nu_0)$ - Velocity $\propto \sqrt{\text{KE}}$
Updated On: May 4, 2026
  • $2v$
  • $2.5 \text{ v}$
  • $3.5 \text{ v}$
  • $4v$
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The Correct Option is A

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