List of top Chemistry Questions on Photoelectric Effect asked in MHT CET

The maximum kinetic energy of photoelectrons depends on:

What is the relationship between maximum kinetic energy and wavelength in the photoelectric effect?

How does the maximum kinetic energy of photoelectrons relate to wavelength (\(\lambda\))?

What is the energy of a photon of frequency \( \nu \)?

Find the energy of a photon with a wavelength of \(4000\,\text{\AA}\). (Take \( h = 6.63 \times 10^{-34}\,\text{Js} \), \( c = 3 \times 10^8\,\text{m/s} \)).

Energy of the incident photons on the metal surface is initially \(4 \text{ W}\) and then \(6 \text{ W}\) where \(W\) is the work function of that metal. The ratio of velocities of emitted photoelectrons is

A photosensitive surface has work function (\phi). If photon of energy (3\phi) falls on this surface, the electron comes out with maximum velocity of (4 \times 10^6 m/s). When photon energy is increased to (7\phi) then maximum velocity will be

The work function of a photosensitive metallic surface is \( h\nu_0 \). If photons of energy \( (2.5)h\nu_0 \) fall on this surface, the electrons come out with maximum velocity ' v '. When the photon energy is increased to \( 7h\nu_0 \), the maximum velocity of photoelectrons will be

From a metallic surface photoelectric emission is observed for frequencies $v_{1}$ and $v_{2}$ ($v_{1}>v_{2}$) of the incident light. The maximum values of the kinetic energy of the photoelectrons emitted in the two cases are in the ratio $1:x$. Hence the threshold frequency of the metallic surface is

When radiation of wavelength '$\lambda$' is incident on a metallic surface, the stopping potential is $4.8 \text{ V}$. If the surface is illuminated with radiation of double the wavelength then the stopping potential becomes $1.6 \text{ V}$. The threshold wavelength for the surface is