Question:medium
The work done in displacing a particle from $y=a$ to $y = 2a$ by a force $F = -\frac{K}{y^2}$ acting along y-axis is
The work done in displacing a particle from $y=a$ to $y = 2a$ by a force $F = -\frac{K}{y^2}$ acting along y-axis is
Show Hint
Work done by a variable force is calculated by integrating the force over the path of displacement. For motion along a single axis, this simplifies to $W = \int_{x_1}^{x_2} F(x) dx$. Remember the power rule for integration: $\int x^n dx = \frac{x^{n+1}}{n+1} + C$.
Updated On: Mar 30, 2026
- $5K/8a$
- $14K/8a^3$
- $-K/a^2$
- $-K/2a$
Show Solution
The Correct Option is D
Solution and Explanation
Was this answer helpful?
0
Top Questions on work, energy and power
- A curve is given between the potential energy \(U\) of a particle and its position on the \(x\)-axis as shown. Given: \[ \tan\theta_1 = 1,\qquad \tan\theta_2 = 3,\qquad \tan\theta_3 = -\frac{1}{2} \] If \(F_{AB}\) is the force acting on the particle during motion from \(A\) to \(B\), similarly \(F_{BC}\), \(F_{CD}\) and \(F_{DE}\) are the forces during \(B\) to \(C\), \(C\) to \(D\) and \(D\) to \(E\) respectively, arrange the magnitudes of these forces in decreasing order.
- JEE Main - 2026
- Physics
- work, energy and power
- A ball of mass 100 g is projected with velocity 20 m/s at $60^\circ$ with horizontal. The decrease in kinetic energy of the ball during the motion from point of projection to highest point is:
- JEE Main - 2026
- Physics
- work, energy and power
- Given below are two statements:
Statement I: An object moves from position \( \vec{r}_1 \) to position \( \vec{r}_2 \) under a conservative force field \( \vec{F} \). The work done by the force is \[ W = -\int_{\vec{r}_1}^{\vec{r}_2} \vec{F} \cdot d\vec{r}. \]
Statement II: Any object moving from one location to another location can follow infinite number of paths. Therefore, the amount of work done by the object changes with the path it follows for a conservative force.
In the light of the above statements, choose the correct answer from the options given below:- JEE Main - 2026
- Physics
- work, energy and power
- A large drum having radius $R$ is spinning around its axis with angular velocity $\omega$, as shown in figure. The minimum value of $\omega$ so that a body of mass $M$ remains stuck to the inner wall of the drum, taking the coefficient of friction between the drum surface and mass $M$ as $\mu$, is :
- JEE Main - 2026
- Physics
- work, energy and power
- Want to practice more? Try solving extra ecology questions todayView All Questions