Question:medium

A block of mass \(m\) is moving on a horizontal frictionless surface with velocity \(v\). It hits a spring of constant \(k\) and compresses it by a distance \(x\). If the initial velocity is doubled, what will be the new compression?

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In spring–block energy problems, equate kinetic energy with spring potential energy. Since \(x^2 \propto v^2\), the compression \(x\) is directly proportional to the velocity \(v\). If velocity doubles, compression doubles; if velocity quadruples, compression quadruples.
Updated On: May 2, 2026
  • \(2x\)
  • \(\sqrt{2}\,x\)
  • \(4x\)
  • \(x/2\)
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The Correct Option is A

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