Question:medium

The work done in assembling three charged particles A, B and C of charges \(2 \times 10^{-5} C\), \(3 \times 10^{-5} C\) and \(4 \times 10^{-5} C\) respectively at the vertices of an equilateral triangle of side 10 cm is \([ \frac{1}{4\pi\varepsilon_0} = 9 \times 10^9 ]\).

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Electrostatic assembly energy = sum of all pairwise interaction energies.
Updated On: Jun 20, 2026
  • 126 J
  • 180 J
  • 234 J
  • 162 J
Show Solution

The Correct Option is C

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