Question

The wavelength of the \(K_\alpha\) line for an element of atomic number 43 is \(\lambda\). Then the wavelength of the \(K_\alpha\) line for an element of atomic number 29 is

• A. \(\left(\frac{43}{29}\right)^2 \lambda\)
• B. \(\left(\frac{42}{28}\right)^2 \lambda\)
• C. \(\left(\frac{9}{4}\right) \lambda\)
• D. \(\left(\frac{4}{9}\right) \lambda\)

Hint:

Moseley's law: \(\sqrt{\nu} = a(Z - b)\). For \(K_\alpha\), \(b = 1\).

Answer 1

The Correct Option is C