Question:easy

The vital capacity, tidal volume, and inspiratory reserve volume of the lungs of a healthy individual are 4600 milliliters (mL), 500 mL, and 2500 mL, respectively. The expiratory reserve volume of the lungs of this individual is mL. (Round off to the nearest integer).

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Vital capacity is tidal volume plus inspiratory reserve volume plus expiratory reserve volume. Just subtract the two known volumes from vital capacity.
Updated On: Aug 7, 2026
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Correct Answer: 1600

Solution and Explanation

Step 1: Picture vital capacity as one bar split into three pieces.
Imagine the full vital capacity, $VC = 4600$ mL, as a single bar. That bar is cut into three non overlapping pieces: tidal volume, inspiratory reserve volume, and expiratory reserve volume. Since the three pieces make up the whole bar with nothing left over, they must add to the total:
\[ TV + IRV + ERV = VC \]

Step 2: Add up the two known pieces first.
We know two of the three pieces: $TV = 500$ mL and $IRV = 2500$ mL.
\[ TV + IRV = 500 + 2500 = 3000 \text{ mL} \]

Step 3: Whatever is left of the bar is the missing piece.
\[ ERV = VC - (TV + IRV) = 4600 - 3000 \]
\[ ERV = 1600 \text{ mL} \]

Step 4: Confirm the split is complete.
Checking the three pieces against the whole: $500 + 2500 + 1600 = 4600$ mL, exactly equal to the stated vital capacity, so no volume is missing or double counted. \[ \boxed{1600 \text{ mL}} \]
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